<?xml version="1.0" encoding="utf-8" standalone="yes"?><rss version="2.0" xmlns:atom="http://www.w3.org/2005/Atom" xmlns:content="http://purl.org/rss/1.0/modules/content/"><channel><title>常用技巧 on ∇Alex的实验室</title><link>https://cn-sunisalex-pages.zh-cn.edgeone.cool/tags/%E5%B8%B8%E7%94%A8%E6%8A%80%E5%B7%A7/</link><description>Recent content in 常用技巧 on ∇Alex的实验室</description><generator>Hugo</generator><language>zh-CN</language><lastBuildDate>Thu, 05 Mar 2026 20:54:13 +0800</lastBuildDate><atom:link href="https://cn-sunisalex-pages.zh-cn.edgeone.cool/tags/%E5%B8%B8%E7%94%A8%E6%8A%80%E5%B7%A7/index.xml" rel="self" type="application/rss+xml"/><item><title>自然对数的估值方法</title><link>https://cn-sunisalex-pages.zh-cn.edgeone.cool/posts/math/lnx-approximation/</link><pubDate>Thu, 05 Mar 2026 20:54:13 +0800</pubDate><guid>https://cn-sunisalex-pages.zh-cn.edgeone.cool/posts/math/lnx-approximation/</guid><description>&lt;h1 id="泰勒展开"&gt;泰勒展开&lt;/h1&gt;
&lt;p&gt;&lt;span class="math math-inline"&gt;
$ \ln (1+x) = x - \frac{x^2}{2} + \frac{x^3}{3} - \cdots + (-1)^{n-1} \frac{x^n}{n} + o(x^n) $
&lt;/span&gt;
需要注意的是,此公式具有收敛半径&lt;span class="math math-inline"&gt;
$R=1$
&lt;/span&gt;,仅适用于&lt;span class="math math-inline"&gt;
$x\approx 0$
&lt;/span&gt;的情况.&lt;/p&gt;
&lt;p&gt;具体内容,可以见&lt;a href="https://www.sunisalex.org/posts/math/taylor-expansion/"&gt;浅谈泰勒展开与高考数学&lt;/a&gt;.&lt;/p&gt;
&lt;h1 id="帕德逼近"&gt;帕德逼近(※)&lt;/h1&gt;
&lt;p&gt;以下是&lt;a href="https://zh.wikipedia.org/zh-sg/%E5%B8%95%E5%BE%B7%E8%BF%91%E4%BC%BC"&gt;维基百科&lt;/a&gt;给出的简介,这里不加赘述.
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